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Maths Lab · Free lesson · 15 minutes

A line tells a story

Connect an equation, a table and a graph—and explain what changes and what stays fixed.

JSS2 · linear relationships

01 · Think first

Start with a question.

A taxi charges ₦500 before it travels, then ₦150 for each kilometre. Is ₦150 the whole fare for a one-kilometre journey?

What you already know
  • Multiply whole numbers
  • Read a coordinate as (x, y)
  • Substitute a number for a letter
Before drawing y = 2x + 1, what will y be when x = 0?

02 · See it

See it · change one thing

Equation → table → graph

Change the rate or starting value. Predict what the line will do, then check.

-4-2024-12-8-44812xy

y = 2x + 1. At x = 1, y = 3. The gradient is 2; the y-intercept is 1.

Values for the current line
x-2-1012
y-3-1135

A zero gradient gives a horizontal line. A negative gradient slopes down as x increases. The axes use different labelled scales: calculate gradient from coordinate changes, not the apparent angle of the line. Context decides which x-values are meaningful.

03 · Show steps · explain why

One justified step at a time.

  1. 1

    y = 2x + 1

    There are two parts: twice x, then add one. The coefficient 2 is the rate of change.

₦500 + ₦150/km × 4 km = ₦1,100

This is an authored teaching example, not a real transport quote.

04 · Mistake clinic

Find the first wrong idea.

Tempting wrong line

For a 4 km taxi trip: C = 150 × 4 = ₦600

Compare the correction and its reason

C = 500 + 150 × 4 = ₦1,100

The first wrong line drops the fixed charge. Test d = 0: the model still charges ₦500, so a model starting at zero cannot describe this fare.

Check: A positive intercept and a rate are different quantities. Name both before calculating.

A mistake is evidence about the next idea to repair. It is not a label for the learner.

05 · Your turn

Try first. Then use a hint.

1. For y = 2x + 1, find y when x = 3.guided practice
2. For y = 2x + 1, find x when y = 9.independent practice
3. A fare is ₦1,400 under C = 500 + 150d. How many kilometres were travelled? Enter the distance in km.far practice

06 · Check & reflect → next step

Understanding includes explaining.

Which can you now explain: the starting value, the rate of change, or how to check a reverse problem?

Choose your next learning need

If substitution is still difficult, practise that prerequisite with a tutor. If it is secure, explain a different line using its table and intercept.

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Source and review status

JEM-J2-M05-001 · Phase 3B · repaired JSS2 Mathematics · Lesson 7 · Cartesian Graphs & Linear Relationships, printed p. 21

This published free lesson contains selected explanations and authored practice. Complete canonical volumes and tutor solutions remain in the protected Content Vault.